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Subject: Re: Ringing in Discontinuous Buck regulator
Date: Wed, 25 Sep 2002 21:14:14 +0800
Organization: Singapore Telecommunications Ltd
References: <3D8F348B.D8BBCEA7@singnet.com.sg> <3D90941F.7A4AB009@singnet.com.sg>
X-Mailer: Mozilla 4.76 [en] (Win98; U)
Thanks for the detailed explanation! I understand the ringing mechanism now. :)
> Hi Bob,
> Regarding your answer....
> > But the non-conducting diode has capacitance to ground (and also there is
> > other stray capacitance as well). So once it goes discontinuous, you have a
> > series resonant tank circuit. The output side of the inductor still has the
> > low impedance of the load connectod to it, and the input end of the inductor
> > is connected through the series capacitance of the diode to ground. So, this
> > L/C tank sinply resonates at its own natural resonance frequency.
> At the instant that the current goes to zero in the inductor, will it stop at
> zero or continue to go to negative? If it goes to zero exactly, how does it
> charge the stray capacitance? Don't you need some energy for oscillation to take
> Am I making sense?
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