Reply-To: "Kevin Aylward"
From: "Kevin Aylward"
References: <firstname.lastname@example.org> <email@example.com> <firstname.lastname@example.org>
Subject: Re: How does a mixer work?
X-Newsreader: Microsoft Outlook Express 6.00.2800.1106
Date: Thu, 17 Oct 2002 11:43:41 +0100
NNTP-Posting-Date: Thu, 17 Oct 2002 11:43:49 BST
"Don Pearce" wrote in message
> On 17 Oct 2002 08:30:56 GMT, email@example.com (Richard
> Steven Walz) wrote:
> >In article <firstname.lastname@example.org>,
> >Asa Cannell wrote:
> >>How does a mixer work? I don't understand why it needs a non-linear
> >>element. I think examples of why a linear element (resistor) wont
> >>would help illustrate why a non-linear element (diode) will. Also,
> >>what does 'mutiply' mean in terms of mixing? What if two DC signals
> >>are applied to a mixer, like 2V and 4V? Will the output be 8V?
> >People use "mix" rather loosely in RF. Actually, a modulator
> >A true audio mixer merely adds. Now when you add sinusoids you can
> >up doing an effective multiplication, but that's merely a
> Pardon? That would be a piece of maths that is new to me. Please
> And of course the word "mixer" has no property of linearity built into
> it. If the RF interpretation is "multiply" and the audio one is "add"
> - they are simply different> Neither is more "right"
Nonsense, the Yanks drive on the wrong side of the road:-)
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