From: Jim Thompson
Subject: Re: How does a mixer work?
References: <email@example.com> <firstname.lastname@example.org>
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Date: Thu, 17 Oct 2002 15:20:57 GMT
NNTP-Posting-Date: Thu, 17 Oct 2002 11:20:57 EDT
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On 17 Oct 2002 08:10:40 -0700,
email@example.com (Asa Cannell),
In Newsgroup: sci.electronics.design,
Entitled: "Re: How does a mixer work?",
Wrote the following:
|Okay now I get the multiply part, where the LO is driven hard,
|multiply the RF/IF input by 1 or 0. But why do we need non-linear
|elements? I understand if you apply two signals to a linear element
|you just get to signals. But I dont see why a non linear element
|suddenly multiplies. Is there some analogy or other type of circuit
|that uses the non linear aspect of diodes in the same or similar way?
Diode equation is VF = kT/q*ln(I/Is)
VF = forward drop of diode
k = Boltzmann's constant
T = temperature in °K
Is = parameter of the silicon process
I = current flowing thru diode
now let I = Idc+I1*sin(omega1*t)+I2*sin(omega2*t)
Now solve for VF.
|"Alfred Lorona" wrote in message news:...
|> No, mixers do not work with DC input signals.
|> 73. AL
| James E.Thompson, P.E. | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona Voice:(480)460-2350 | |
| Jim-T@analog_innovations.com Fax:(480)460-2142 | Brass Rat |
| http://www.analog-innovations.com | 1962 |
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