Reply-To: "Dave M"
From: "Dave M"
Subject: Re: Interesting problem to solve
X-Newsreader: Microsoft Outlook Express 6.00.2600.0000
Date: Sat, 19 Oct 2002 00:09:50 GMT
NNTP-Posting-Date: Sat, 19 Oct 2002 00:09:50 GMT
Organization: AT&T Worldnet
If the two signals are the same amplitude, I would use a couple of
comparators set to trip at the same voltage (same reference voltage), and
trigger a counter on with the leading edge of the first comparator output,
then trigger it off with the leading edge of the second comparator output.
The time difference is the count in the counter, multiplied by the clock
period of the counter. For instance, if the counter is clocked at 1usec
intervals, and the counter contains a count of 25, then the time difference
is ummm.... 25 usec.
Dave M firstname.lastname@example.org
Remove the xx for my correct email address
"Brill Pappin" wrote in message
> I've got an interesting problem to solve.
> I want to measure the time difference between the same sign wave arriving
> two different inputs one slightly behind the other.
> The idea being that one (variable) sign wave comes in one input, then the
> other (same signal, just delayed for a short duration, maybe in the 10s of
> uSec) behind it, comes in the other input...
> I'm not sure how I would do it... maybe try and measure the amplitude and
> look for a repeating pattern.
> Anyone have any ideas?
> - Brill Pappin