From: "Brill Pappin"
References: <3DAFBB9D.58C1F0BB@scazon.com> <3DAFF518.2F4DBF7B@juno.com>
Subject: Re: Interesting problem to solve
X-Newsreader: Microsoft Outlook Express 6.00.2800.1106
Date: Sat, 19 Oct 2002 09:12:11 GMT
NNTP-Posting-Date: Sat, 19 Oct 2002 05:12:11 EDT
Actually, when I started thinking about this, I was thinking of how your
ears hear sound, as a delayed sign wave (the sound) as it hits first one
ear, then the other.
I didn't mention it until now because that not really what I'm pondering,
only what got me to thinking in the first place.
- Brill Pappin
"mike" wrote in message
> I'm gonna go out on a limb here and state that if the signals are
> and continuous, you have no way to determine whether they are delayed
> or out of phase by more than one cycle...unless you have additional
> information available.
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> Brill Pappin wrote:
> > Yes, that would work well for a single period, but if the signals are
> > than that apart, I wouldn't be able to tell that I had to skip one.
> > What I really want to measure is the vector of the difference between
> > two signals. but if I've got an amplitude of say 2uS, and I delay the
> > by 6uS, I would get a value of 2uS if measuring the 0 crossings (I'm
> > assuming I'm getting more than a single period).
> > - Brill Pappin
> > "Paul Burke" wrote in message
> > news:3DAFBB9D.58C1F0BB@scazon.com...
> > > Brill Pappin wrote:
> > > >
> > > > I've got an interesting problem to solve.
> > > >
> > > > I want to measure the time difference between the same sign wave
> > arriving at
> > > > two different inputs one slightly behind the other.
> > > >
> > >
> > > Since the two sinewaves are variable in amplitude, you need to measure
> > > between the zero crossings. Use comparators to square up the
> > > then start your counter on the first rising edge detected. Stop the
> > > counter when both inputs are high.
> > >
> > > Paul Burke