From: Lizard Blizzard
Subject: Re: V regulator input cap size?
Date: Tue, 22 Oct 2002 09:16:01 -0700
References: <0001HW.B9D991AD000C5917163F7590@news.covad.net> <email@example.com> <0001HW.B9D9CD54001A5D15163F7590@news.covad.net> <3DB4D802.519D9110@bellatlantic.net>
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> That 300 ma is probably high - but your minimum is 200 ma,
> which still leaves a total of about 6.2 watts to be dissipated.
> Finding a lower current relay would be a big help.
That is a really good idea. Use a much higher voltage, much lower
current relay. The 28V coil relay would cut the current to less than
half of that for a 12V relay. The relay would be connected to the PS
ahead of the regulator. This is often done in equipment for this very
reason, to cut down on the regulator power demands. It allows cheaper
equipment to use a low power regulator, or even just an inexpensive
zener diode shunt regulator.
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PUNCTUATION - Apostrophe
Incorrect uses: (i) the apostrophe must not be used with a plural
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