From: Don Pearce
Subject: Re: How does a mixer work?
Date: Thu, 24 Oct 2002 07:44:32 +0430
References: <firstname.lastname@example.org> <email@example.com> <firstname.lastname@example.org>
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On 23 Oct 2002 21:46:06 GMT, email@example.com (Richard
Steven Walz) wrote:
>In article ,
>Don Pearce wrote:
>>On 21 Oct 2002 06:55:46 GMT, firstname.lastname@example.org (Richard
>>Steven Walz) wrote:
>>>>>You're in the wrong crowd for your pretense, you piece of shit.
>>>>>We all know what I meant, AND that you're a disingenuous asshole!
>>>>So come on - just tell us what you meant. Did you mean:
>>>>"When you add sine waves you wind up effectively adding them"?
>>>>That would be correct, but hardly illuminating.
>>>NO, you STUPID PIECE OF SHIT!!
>>>sin(x)*sin(y) = (1/2)cos(x+y) - (1/2)cos(x-y)
>>>What in the fuck is WRONG with you!??
>>Now I understand! You think that because sin(x)*sin(y) can be
>>expressed in cos terms of (x+y) then multiplying the sinusoids on the
>>left is effectively the same as adding the coses (which we accept as
>>sinusoids) on the right!
>No, that's what YOU think I think. You didn't even quote me properly
>or else you'd know better, now just go away like a good little piece
>of shit waste of time.
OK, now you've really got me puzzled. The only pair of trig identities
I can see summed (OK, it is a minus, but who's counting?) are those
coses - which I am also happy to consider sinusoids for the purposes
of the game - could I be more reasonable?
And now you say it isn't those at all. I give up.