From: "news.cable.ntlworld.com"
Newsgroups: sci.electronics.design
References: <3200347.0210251320.738f5ebc@posting.google.com>
Subject: Re: Output Impedence
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Date: Sat, 26 Oct 2002 16:41:14 +0100
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Cheers Guys,
The reason I want to know is because I have a soundcard that is conectted to
a mixing desk via a line out. However, there is really bad hum on the line
(about -36db) which is noticably audiable. I have checked the desk,
computer, soundcard and cables and have come to the conclusion that is a
earth loop problem.
I am going to put an isolation TX 1:1 on the soundcard output but all the
specs I have seen on different TX's state input/output impedences. Thats
why I need to know.
Thats unless it doesn't really matter ??
Thanks,
Gavin.
"Tom Bruhns" wrote in message
news:3200347.0210251320.738f5ebc@posting.google.com...
> "news.cable.ntlworld.com" wrote in message
news:...
> > Hi,
> >
> > How would I go about getting the output impedence of a computer sound
card.
>
> Look up the specs for the card, or measure it. Unfortunately, the
> term "output impedance" is tossed about rather freely. Technically,
> it should mean the source impedance you see looking back into that
> output, but often people use the same term to mean "recommended load
> impedance." For example, the output impedance of a typical stereo
> amplifier is a fraction of an ohm, but the recommended range of load
> impedances might be "greater than 4 ohms" or "greater than 6 ohms" or
> whatever. That's determined by how much heat may safely be dissipated
> in the amplifier, and what distortion level can be tolerated, and a
> few other such things.
>
> It should be safe to put a standard headphone load on a headphone
> output, or an 8 ohm speaker load on a speaker output, or a typical
> line load on a line output. If you really must measure the output
> (source) impedance, output a constant level, and put a reasonable load
> on the output and note how much the output voltage drops. If the
> source impedance and load are both resistive, then Vl/Vo = Rl/(Ro+Rl),
> where Vl is the loaded output voltage, Vo is the open-circuit output
> voltage, Rl is the load resistance, and Ro is the output source
> resistance. So, for instance, if you don't see any significant drop
> in voltage when you put the load on, Ro is much smaller than Rl. If
> the voltage drops to half, Rl=Ro. It's likely to be somewhat
> frequency dependent.
>
> Cheers,
> Tom