From: John Woodgate
Subject: Re: Aylward, Engelhardt: Noise in a transient sim?
Date: Sun, 27 Oct 2002 22:24:30 +0000
Organization: JMWA Electronics Consultancy
Reply-To: John Woodgate
NNTP-Posting-Date: Mon, 28 Oct 2002 06:38:29 +0000 (UTC)
X-Newsreader: Turnpike (32) Version 4.01 <5Z8C9wtxbnpWyFnyfFzqmVF739>
I read in sci.electronics.design that Kevin Aylward
wrote (in ) about 'Aylward, Engelhardt: Noise in a transient sim?', on
Sun, 27 Oct 2002:
>"John Woodgate" wrote in message
>> I read in sci.electronics.design that Kevin Aylward
>> wrote (in
>> ntli.net>) about 'Aylward, Engelhardt: Noise in a transient sim?', on
>> Sun, 27 Oct 2002:
>> > There is *nothing* wrong in my
>> >explanation, imo, at all.
>> Ah, 'imo'. No, it's not *wrong*, but it isn't getting across.
>> > Mike simple won't listen! Its not always the
>> >fault of the teacher while a student wont understand.
>> No, not always, but it takes two to tango, or, in this case, step on
>> each other's toes.
>> Your post contained a perfect example of 'talking past'. What is the
>> standard deviation of a sinusoid? Zero *in the frequency domain*
>> (neglecting the 'Big Bang to Heat Death' formality). Equal to the
>> value *in the time domain*. Both right, apparently mutually
>> contradictory, but not.
>I don't understand what you second claim is. Are you saying that the rms
>value in the time domain is equal to the rms value in the frequency
>domain, if so you have missed something, cos this aint so.
No, I am not saying that. The third sentence, like the second, is an
answer to the question in the first sentence. The r.m.s. value of a
sinusoid is also the standard deviation - the formulae are the same:
Xrms = 1/2pi| Xsin^2wt d(wt) = Xbar
Regards, John Woodgate, OOO - Own Opinions Only. http://www.jmwa.demon.co.uk
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