Reply-To: "Kevin Aylward"
From: "Kevin Aylward"
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Subject: Re: Aylward, Engelhardt: Noise in a transient sim?
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Date: Mon, 28 Oct 2002 07:46:14 -0000
NNTP-Posting-Date: Mon, 28 Oct 2002 07:46:18 GMT
"John Woodgate" wrote in message
> I read in sci.electronics.design that Kevin Aylward
> wrote (in
r.ntli.net>) about 'Aylward, Engelhardt: Noise in a transient sim?',
> Sun, 27 Oct 2002:
> >"John Woodgate" wrote in message
> >> I read in sci.electronics.design that Kevin Aylward
> >> wrote (in
> > >> ntli.net>) about 'Aylward, Engelhardt: Noise in a transient sim?',
> >> Sun, 27 Oct 2002:
> >> > There is *nothing* wrong in my
> >> >explanation, imo, at all.
> >> Ah, 'imo'. No, it's not *wrong*, but it isn't getting across.
> >> > Mike simple won't listen! Its not always the
> >> >fault of the teacher while a student wont understand.
> >> No, not always, but it takes two to tango, or, in this case, step
> >> each other's toes.
> >> Your post contained a perfect example of 'talking past'. What is
> >> standard deviation of a sinusoid? Zero *in the frequency domain*
> >> (neglecting the 'Big Bang to Heat Death' formality). Equal to the
> >> value *in the time domain*. Both right, apparently mutually
> >> contradictory, but not.
> >I don't understand what you second claim is. Are you saying that the
> >value in the time domain is equal to the rms value in the frequency
> >domain, if so you have missed something, cos this aint so.
> No, I am not saying that. The third sentence, like the second, is an
> answer to the question in the first sentence. The r.m.s. value of a
> sinusoid is also the standard deviation - the formulae are the same:
> f 2pi
> Xrms = 1/2pi| Xsin^2wt d(wt) = Xbar
> j 0
Exactly, well you forgot te root the whole expression, but anyway. I
think this is what threw some people that made them introduce noise into
the discussion, when I said standard deviation.
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