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From: "Frank Bemelman"
References: <3DBD8BF0.email@example.com> <firstname.lastname@example.org> <3DBE4CE2.email@example.com>
Subject: Re: Philips XA architecture design
Date: Tue, 29 Oct 2002 18:52:16 +0100
X-Newsreader: Microsoft Outlook Express 6.00.2600.0000
Organization: EuroNet Internet
NNTP-Posting-Date: 29 Oct 2002 16:54:51 GMT
"Tim Kortekaas" schreef in bericht
> Frank Bemelman wrote:
> < ...snip... >
> O.K. It's getting clearer and clearer to me.
> I think I know now how to connect a 16 bit ROM to the microcontroller.
> But now a question about the programming. When I grab the output of my
> Now think of the 16bit EPROM. It has 64k adresses of double byte words.
> Look at the third line. Is says the length of the data record is 0x20.
> These are 0x20 bytes of data and the address where it's all happening is
> 0x0120. When each address of the EPROM can hold up to two bytes, the
> total memory addresses used is divided by 2 (2 bytes per address). So
> the address on the next line (which is 0x0140) should be 0x0130.
> Or am I making a terrible mistake again?
I don't know. To me it seems that a compiler couldn't care less if
you want to use 16bit eproms or 8bit eproms, and how your hardware
deals with it. So, the file is - I assume - how the bytes are to be
stored into an 8bit eprom. Some programmers have options to shuffle
or split the bytes, if the file is 8bit and you use a 16bit hardware
setup, but actually use 2 seperate 8bit eproms to accomplish this.
In that case, both 8bit eproms are connected to the same adresses,
and one eprom delivering the low bytes (even adresses) and another
one delivering the high bytes (odd adresses).
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