The Cyber-Spy.Com Usenet Archive Feeds Directly
From The Open And Publicly Available Newsgroup
This Group And Thousands Of Others Are Available
On Most IS NNTP News Servers On Port 119.
Cyber-Spy.Com Is NOT Responsible For Any Topic,
Opinions Or Content Posted To This Or Any Other
Newsgroup. This Web Archive Of The Newsgroup And
Posts Are For Informational Purposes Only.
From: Fred Bloggs
User-Agent: Mozilla/5.0 (Windows; U; Win 9x 4.90; en-US; rv:1.0.1) Gecko/20020823 Netscape/7.0
X-Accept-Language: en-us, en
Subject: Re: Battery Circuit
References: <email@example.com> <3DC40E96.firstname.lastname@example.org> <email@example.com> <3DC4714E.firstname.lastname@example.org> <email@example.com>
Date: Sun, 03 Nov 2002 19:23:08 GMT
NNTP-Posting-Date: Sun, 03 Nov 2002 11:23:08 PST
Organization: EarthLink Inc. -- http://www.EarthLink.net
The best that I can determine from the Hawker manual is 15-20 minutes
maximum at this discharge rate. When the battery reaches critical
discharge, the output voltage will start to fall rapidly, but until that
time, it will be on a fairly gentle glide slope of a few millivolts per
minute decline versus 100mV per minute as it takes the end of discharge
> 1.5 - 1.6 amps
> "Fred Bloggs" wrote in message
>>>*** post for FREE via your newsreader at post.newsfeed.com ***
>>>I know the useable range, I need to know how low the
>>>battery voltage can go under load without damage to
>>>the SLA battery.
>>I see here that you are interested in time. This again depends on the
>>discharge rate at cutout. If you are discharging at 0.1C then it may
>>take hours before you go beyond damage level, and if it is at 2C then
>>you will be down to minutes. So the answer to your question depends on
>>the discharge rate.
> -----= Posted via Newsfeed.Com, Uncensored Usenet News =-----
> http://www.newsfeed.com - The #1 Newsgroup Service in the World!
> -----== 100,000 Groups! - 19 Servers! - Unlimited Download! =-----
Go Back To The Cyber-Spy.Com
Usenet Web Archive Index Of
The sci.electronics.design Newsgroup