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From: John Popelish
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X-Mailer: Mozilla 4.7 [en] (Win98; U)
Subject: Re: O.T. Math help
Date: Tue, 05 Nov 2002 02:45:01 GMT
NNTP-Posting-Date: Mon, 04 Nov 2002 21:45:01 EST
> I'm trying to suspend olive oil in an alcohol/water mix.
> If the density of the alcohol/water is proper the olive oil will
> not float or sink -----very fast.
> Using my numbers ;-)
> Olive oil-----.904
> How do I calculate the ratio of water to alcohol to equal
> the density of the olive oil. I know the answer is about 59%
> water and 41% alcohol.
> This is not homework, I'm trying to teach my 11 year old
> some science and got stuck when I could do the math properly.
Unfortunately there is not an accurate way to predict the percentages,
because alcohol and water do not just mix, the way oil and water do,
but get chemically involved with each other in subtle ways that
affects the space each molecule takes up.
That said, I think you get a rough idea of the final density by
multiplying the percentage as a fraction or each component times the
density of each component and then adding those results together.
So: (F * .984) + ((1-F) * .786) = .904
where F is the fraction by volume of the alcohol water mix that is
water (.59 in your example).
You can rearrange that and solve for F.
So your example solved by this method gives a prediction of the
mixture having a density of .9028 The reaction I alluded to, raises
the density, so this prediction is a bit low.
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