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From: Roy McCammon
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Subject: Re: Deriving H for magnetic cores
References: <3DFF8FA6.4593A00A@mmm.com.DELETETHIS> <3DFFE9DB.1BEFBBE3@earthlink.net> <3E008AB8.141E41D5@mmm.com.DELETETHIS> <3E010057.FD7DACF3@mmm.com.DELETETHIS>
Date: Thu, 26 Dec 2002 22:16:20 GMT
NNTP-Posting-Date: Thu, 26 Dec 2002 16:16:20 CST
Organization: Road Runner - Texas
John Woodgate wrote:
> That is quite unfair and you know it. H = I/2[pi]r is not 'qualitative',
> nor is the argument that you cannot break the closed contours of
> constant H by deforming the conductor.
you wound me sir. It is true that I sometimes
speak incorrectly, but never when I know it.
Lets look at a similar situation in circuit
theory. The cube made of identical resisters.
Now, when we teach circuit theory, we teach
how to use node or mesh analysis to generate
A system of simultaneous linear equations which
may be solved to node voltages of mesh currents.
Then we present the cube. The student may start
off writing 6 equations, but we chuckle and
laugh and show how to use symmetry in this case
arrive at the answer with much less effort.
But the way we teach magnetics is analogous to
starting with the cube and symmetry and that
dropping the subject without ever teaching the
more general analysis. The student thinks
he knows all there is too it, but the first
time he encounters a non symmetric situation,
he is lost.
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