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From: email@example.com (Paul Burridge)
Subject: Re: Transistor amplifiers v. frequency in SPICE
Date: 12 Jan 2003 04:53:20 -0800
NNTP-Posting-Date: 12 Jan 2003 12:53:20 GMT
Mike Monett wrote in message news:<3E20D1C8.166C@sneakemail.com>...
> Paul Burridge wrote:
> [... see original for CKT file]
> I have to admire your energy and persistence. SPICE is not easy to learn,
> and you are doing a good job of asking the right questions.
THanks, Mike. I can use all the encouragement I get!
> A couple of quick comments. Your SPICE should be able to plot the AC
> response curve instead of having to do each frequency manually. What
> version are you using?
I think the version is shown on the .ckt file I posted. However, I'll
the instruction line for the AC sweep and maybe from that you can see
> The emitter and collector resistors are way too high for the frequency
> response you are asking. MicroCap calculates the ft at 1.72MHz under
> these conditions. Here are some suggestions you might want to try:
> Change the resistors to the following values:
> R1 = 1k
> R8 = 1k
> R7 = 750
> R2 = 470
> Change C2 to 1uF.
> Now plot the frequency response. It should improve, but it still falls
> off rapidly.
Thanks for that. The reason for the high value resistors was that I
trying to keep Zin as high as possible, since the real signal source
I am modelling has a quite high Z. Yes, I know. Get myself a FET! :-)
> You should be able to find the operating point information in the
> printout, and it should indicate the transistor parameters such as
> collector, base and emitter current, and also the beta and ft. These are
> rough guides to how the transistor is functioning.
Indeed. I do use the DC .op function quite often and find it very
> Try changing to a higher frequency transistor like the MMBR941:
> .MODEL MMBR941 NPN(BF=110 VAF=80 VAR=8.0 RC=.54 RB=.08 RE=.009 IKF=35M
> + ISE=0.45E-14 TF=0.111E-10 TR=0.80E-09 ITF=0.20E-01 VTF=0.33E+01
> + CJC=0.074E-12 CJE=0.064E-12 XTI=3.0 NE=1.5 ISC=0.15E-14 EG=1.11
> + XTB=1.5 BR=2.86 VJC=0.75 VJE=0.75 IS=0.50E-15 MJC=0.33 MJE=0.33 XTF=4.0
> + IKR=0.35E-01 KF=0.1E-14 NC=1.7 FC=0.50 RBM=.06 IRB=0.50E-02 XCJC=0.5)
> Now you should see a flat frequency response past 1GHz. Don't believe it
> for a minute:)
Thanks for posting the model. If it's not in my library I'll add it.
> Add a 50 ohm resistor in series with the signal source. The frequency
> response falls off dramatically.
> Add a 5pF cap from the collector to ground to simulate stray trace and
> pin capacity. The frequency response falls even faster.
> Add a 1pf from the collector to the base. The frequency response falls
> faster still.
> These are simple ways to see how a circuit is working, and to get a
> feeling for the real-world effect of strays. It tells you for wideband
> circuits, you need low impedance which means high current.
Fascinating. Thanks for a valuable insight into the difference between
SPICEWORLD and the real world! BTW and on this subject, would I be
to assume that SPICE models take no account of component lead-length?
example, a real-world coupling capacitor has an optimal value with
impedance at the desired (radio)frequency due to the inductance of the
creating a series tuned circuit of sorts, whereas the SPICE capacitor
"perfect" and bigger (values)are always better and present less
> But first thing is to get SPICE to plot the AC response curves for you.
> Lets see if we can help!
Many thanks again. I'm always grateful for informed input to my
I'll establish the relevant instruction sequence and append it to this
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