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From: John Woodgate
Subject: Re: PSU ripple current
Date: Tue, 14 Jan 2003 19:40:24 +0000
Organization: JMWA Electronics Consultancy
Reply-To: John Woodgate
NNTP-Posting-Date: Tue, 14 Jan 2003 21:31:34 +0000 (UTC)
X-Newsreader: Turnpike (32) Version 4.01 <5Z8C9wtxbnpWyFnyfFzqmVF739>
I read in sci.electronics.design that Phil Allison
wrote (in ) about 'PSU
ripple current', on Tue, 14 Jan 2003:
>BTW If the ripple voltage were a really a symmetrical triangle wave then
>by differentiation the ripple current in the cap *must* be a square wave of
>value equal to the DC load current.
> The normal ripple wave is a sawtooth with steep rise and slower
>fall and this differentiates to a pluse wave with a mark space ratio of
>about 3:1. The average of this wave must be zero for the cap to stay at
>the same voltage so the charge current must be 3 times the discharge - ie
>+3 amps for 2.5mS followed by - 1 amp for 7.5mS.
> This would have an rms value of 1.73 amps.
He keeps doing this: super stuff. But WHY can't he refuse to get
involved in flame wars?
Regards, John Woodgate, OOO - Own Opinions Only. http://www.jmwa.demon.co.uk
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