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Subject: RF-Amplifiers (again)
Date: 15 Jan 2003 14:25:28 GMT
Organization: Your Company
NNTP-Posting-Host: ms137dhcp147.marine.usf.edu (126.96.36.199)
A couple of days ago I asked you, where to buy an amplifier.
Thanks to all of you!! I think I found what i want. but there are still
some questions about it.
The amplifiers are specified for certain bandwidth.
The Output power is related to the output impedance (mostly 50 Ohms)
But, what I need is a statement about the output voltage.
So, my thinking of calculating the output voltage is:
1. R = U/I
2. P = R*I^2 ; P=50Watts , R=50Ohm (Output Inpedance)
2.a I = 1 Amp
Inserting I into 1. and R = 50Ohms I get the output voltage:
U = 50 V (for a high impedance load)
If I have a 50 Ohm load the maximum output voltage drops to 25V,
because of the impedance matching.
Is that right??
I'm not a specialist so may you give me a advice please??
(maybe I'm going to be a specialist with your help) ;-)
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